3.3.70 \(\int \frac {(g \sec (e+f x))^{3/2} \sqrt {c+d \sec (e+f x)}}{a+b \sec (e+f x)} \, dx\) [270]

3.3.70.1 Optimal result
3.3.70.2 Mathematica [C] (verified)
3.3.70.3 Rubi [A] (verified)
3.3.70.4 Maple [C] (verified)
3.3.70.5 Fricas [F(-1)]
3.3.70.6 Sympy [F]
3.3.70.7 Maxima [F]
3.3.70.8 Giac [F]
3.3.70.9 Mupad [F(-1)]

3.3.70.1 Optimal result

Integrand size = 39, antiderivative size = 170 \[ \int \frac {(g \sec (e+f x))^{3/2} \sqrt {c+d \sec (e+f x)}}{a+b \sec (e+f x)} \, dx=\frac {2 d g \sqrt {\frac {d+c \cos (e+f x)}{c+d}} \operatorname {EllipticPi}\left (2,\frac {1}{2} (e+f x),\frac {2 c}{c+d}\right ) \sqrt {g \sec (e+f x)}}{b f \sqrt {c+d \sec (e+f x)}}+\frac {2 (b c-a d) g \sqrt {\frac {d+c \cos (e+f x)}{c+d}} \operatorname {EllipticPi}\left (\frac {2 a}{a+b},\frac {1}{2} (e+f x),\frac {2 c}{c+d}\right ) \sqrt {g \sec (e+f x)}}{b (a+b) f \sqrt {c+d \sec (e+f x)}} \]

output
2*d*g*(cos(1/2*f*x+1/2*e)^2)^(1/2)/cos(1/2*f*x+1/2*e)*EllipticPi(sin(1/2*f 
*x+1/2*e),2,2^(1/2)*(c/(c+d))^(1/2))*((d+c*cos(f*x+e))/(c+d))^(1/2)*(g*sec 
(f*x+e))^(1/2)/b/f/(c+d*sec(f*x+e))^(1/2)+2*(-a*d+b*c)*g*(cos(1/2*f*x+1/2* 
e)^2)^(1/2)/cos(1/2*f*x+1/2*e)*EllipticPi(sin(1/2*f*x+1/2*e),2*a/(a+b),2^( 
1/2)*(c/(c+d))^(1/2))*((d+c*cos(f*x+e))/(c+d))^(1/2)*(g*sec(f*x+e))^(1/2)/ 
b/(a+b)/f/(c+d*sec(f*x+e))^(1/2)
 
3.3.70.2 Mathematica [C] (verified)

Result contains complex when optimal does not.

Time = 25.51 (sec) , antiderivative size = 223, normalized size of antiderivative = 1.31 \[ \int \frac {(g \sec (e+f x))^{3/2} \sqrt {c+d \sec (e+f x)}}{a+b \sec (e+f x)} \, dx=-\frac {2 i g \sqrt {-\frac {c (-1+\cos (e+f x))}{c+d}} \sqrt {\frac {c (1+\cos (e+f x))}{c-d}} \cot (e+f x) \left (\operatorname {EllipticPi}\left (1-\frac {c}{d},i \text {arcsinh}\left (\sqrt {\frac {1}{c-d}} \sqrt {d+c \cos (e+f x)}\right ),\frac {-c+d}{c+d}\right )-\operatorname {EllipticPi}\left (\frac {a (-c+d)}{-b c+a d},i \text {arcsinh}\left (\sqrt {\frac {1}{c-d}} \sqrt {d+c \cos (e+f x)}\right ),\frac {-c+d}{c+d}\right )\right ) \sqrt {g \sec (e+f x)} \sqrt {c+d \sec (e+f x)}}{b \sqrt {\frac {1}{c-d}} f \sqrt {d+c \cos (e+f x)}} \]

input
Integrate[((g*Sec[e + f*x])^(3/2)*Sqrt[c + d*Sec[e + f*x]])/(a + b*Sec[e + 
 f*x]),x]
 
output
((-2*I)*g*Sqrt[-((c*(-1 + Cos[e + f*x]))/(c + d))]*Sqrt[(c*(1 + Cos[e + f* 
x]))/(c - d)]*Cot[e + f*x]*(EllipticPi[1 - c/d, I*ArcSinh[Sqrt[(c - d)^(-1 
)]*Sqrt[d + c*Cos[e + f*x]]], (-c + d)/(c + d)] - EllipticPi[(a*(-c + d))/ 
(-(b*c) + a*d), I*ArcSinh[Sqrt[(c - d)^(-1)]*Sqrt[d + c*Cos[e + f*x]]], (- 
c + d)/(c + d)])*Sqrt[g*Sec[e + f*x]]*Sqrt[c + d*Sec[e + f*x]])/(b*Sqrt[(c 
 - d)^(-1)]*f*Sqrt[d + c*Cos[e + f*x]])
 
3.3.70.3 Rubi [A] (verified)

Time = 2.05 (sec) , antiderivative size = 170, normalized size of antiderivative = 1.00, number of steps used = 13, number of rules used = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {3042, 4459, 3042, 4346, 3042, 3286, 3042, 3284, 4463, 3042, 3286, 3042, 3284}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(g \sec (e+f x))^{3/2} \sqrt {c+d \sec (e+f x)}}{a+b \sec (e+f x)} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {\left (g \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{3/2} \sqrt {c+d \csc \left (e+f x+\frac {\pi }{2}\right )}}{a+b \csc \left (e+f x+\frac {\pi }{2}\right )}dx\)

\(\Big \downarrow \) 4459

\(\displaystyle \frac {(b c-a d) \int \frac {(g \sec (e+f x))^{3/2}}{(a+b \sec (e+f x)) \sqrt {c+d \sec (e+f x)}}dx}{b}+\frac {d \int \frac {(g \sec (e+f x))^{3/2}}{\sqrt {c+d \sec (e+f x)}}dx}{b}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {(b c-a d) \int \frac {\left (g \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{3/2}}{\left (a+b \csc \left (e+f x+\frac {\pi }{2}\right )\right ) \sqrt {c+d \csc \left (e+f x+\frac {\pi }{2}\right )}}dx}{b}+\frac {d \int \frac {\left (g \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{3/2}}{\sqrt {c+d \csc \left (e+f x+\frac {\pi }{2}\right )}}dx}{b}\)

\(\Big \downarrow \) 4346

\(\displaystyle \frac {(b c-a d) \int \frac {\left (g \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{3/2}}{\left (a+b \csc \left (e+f x+\frac {\pi }{2}\right )\right ) \sqrt {c+d \csc \left (e+f x+\frac {\pi }{2}\right )}}dx}{b}+\frac {d g \sqrt {g \sec (e+f x)} \sqrt {c \cos (e+f x)+d} \int \frac {\sec (e+f x)}{\sqrt {d+c \cos (e+f x)}}dx}{b \sqrt {c+d \sec (e+f x)}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {(b c-a d) \int \frac {\left (g \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{3/2}}{\left (a+b \csc \left (e+f x+\frac {\pi }{2}\right )\right ) \sqrt {c+d \csc \left (e+f x+\frac {\pi }{2}\right )}}dx}{b}+\frac {d g \sqrt {g \sec (e+f x)} \sqrt {c \cos (e+f x)+d} \int \frac {1}{\sin \left (e+f x+\frac {\pi }{2}\right ) \sqrt {d+c \sin \left (e+f x+\frac {\pi }{2}\right )}}dx}{b \sqrt {c+d \sec (e+f x)}}\)

\(\Big \downarrow \) 3286

\(\displaystyle \frac {(b c-a d) \int \frac {\left (g \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{3/2}}{\left (a+b \csc \left (e+f x+\frac {\pi }{2}\right )\right ) \sqrt {c+d \csc \left (e+f x+\frac {\pi }{2}\right )}}dx}{b}+\frac {d g \sqrt {g \sec (e+f x)} \sqrt {\frac {c \cos (e+f x)+d}{c+d}} \int \frac {\sec (e+f x)}{\sqrt {\frac {d}{c+d}+\frac {c \cos (e+f x)}{c+d}}}dx}{b \sqrt {c+d \sec (e+f x)}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {(b c-a d) \int \frac {\left (g \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{3/2}}{\left (a+b \csc \left (e+f x+\frac {\pi }{2}\right )\right ) \sqrt {c+d \csc \left (e+f x+\frac {\pi }{2}\right )}}dx}{b}+\frac {d g \sqrt {g \sec (e+f x)} \sqrt {\frac {c \cos (e+f x)+d}{c+d}} \int \frac {1}{\sin \left (e+f x+\frac {\pi }{2}\right ) \sqrt {\frac {d}{c+d}+\frac {c \sin \left (e+f x+\frac {\pi }{2}\right )}{c+d}}}dx}{b \sqrt {c+d \sec (e+f x)}}\)

\(\Big \downarrow \) 3284

\(\displaystyle \frac {(b c-a d) \int \frac {\left (g \csc \left (e+f x+\frac {\pi }{2}\right )\right )^{3/2}}{\left (a+b \csc \left (e+f x+\frac {\pi }{2}\right )\right ) \sqrt {c+d \csc \left (e+f x+\frac {\pi }{2}\right )}}dx}{b}+\frac {2 d g \sqrt {g \sec (e+f x)} \sqrt {\frac {c \cos (e+f x)+d}{c+d}} \operatorname {EllipticPi}\left (2,\frac {1}{2} (e+f x),\frac {2 c}{c+d}\right )}{b f \sqrt {c+d \sec (e+f x)}}\)

\(\Big \downarrow \) 4463

\(\displaystyle \frac {g (b c-a d) \sqrt {g \sec (e+f x)} \sqrt {c \cos (e+f x)+d} \int \frac {1}{(b+a \cos (e+f x)) \sqrt {d+c \cos (e+f x)}}dx}{b \sqrt {c+d \sec (e+f x)}}+\frac {2 d g \sqrt {g \sec (e+f x)} \sqrt {\frac {c \cos (e+f x)+d}{c+d}} \operatorname {EllipticPi}\left (2,\frac {1}{2} (e+f x),\frac {2 c}{c+d}\right )}{b f \sqrt {c+d \sec (e+f x)}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {g (b c-a d) \sqrt {g \sec (e+f x)} \sqrt {c \cos (e+f x)+d} \int \frac {1}{\left (b+a \sin \left (e+f x+\frac {\pi }{2}\right )\right ) \sqrt {d+c \sin \left (e+f x+\frac {\pi }{2}\right )}}dx}{b \sqrt {c+d \sec (e+f x)}}+\frac {2 d g \sqrt {g \sec (e+f x)} \sqrt {\frac {c \cos (e+f x)+d}{c+d}} \operatorname {EllipticPi}\left (2,\frac {1}{2} (e+f x),\frac {2 c}{c+d}\right )}{b f \sqrt {c+d \sec (e+f x)}}\)

\(\Big \downarrow \) 3286

\(\displaystyle \frac {g (b c-a d) \sqrt {g \sec (e+f x)} \sqrt {\frac {c \cos (e+f x)+d}{c+d}} \int \frac {1}{(b+a \cos (e+f x)) \sqrt {\frac {d}{c+d}+\frac {c \cos (e+f x)}{c+d}}}dx}{b \sqrt {c+d \sec (e+f x)}}+\frac {2 d g \sqrt {g \sec (e+f x)} \sqrt {\frac {c \cos (e+f x)+d}{c+d}} \operatorname {EllipticPi}\left (2,\frac {1}{2} (e+f x),\frac {2 c}{c+d}\right )}{b f \sqrt {c+d \sec (e+f x)}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {g (b c-a d) \sqrt {g \sec (e+f x)} \sqrt {\frac {c \cos (e+f x)+d}{c+d}} \int \frac {1}{\left (b+a \sin \left (e+f x+\frac {\pi }{2}\right )\right ) \sqrt {\frac {d}{c+d}+\frac {c \sin \left (e+f x+\frac {\pi }{2}\right )}{c+d}}}dx}{b \sqrt {c+d \sec (e+f x)}}+\frac {2 d g \sqrt {g \sec (e+f x)} \sqrt {\frac {c \cos (e+f x)+d}{c+d}} \operatorname {EllipticPi}\left (2,\frac {1}{2} (e+f x),\frac {2 c}{c+d}\right )}{b f \sqrt {c+d \sec (e+f x)}}\)

\(\Big \downarrow \) 3284

\(\displaystyle \frac {2 g (b c-a d) \sqrt {g \sec (e+f x)} \sqrt {\frac {c \cos (e+f x)+d}{c+d}} \operatorname {EllipticPi}\left (\frac {2 a}{a+b},\frac {1}{2} (e+f x),\frac {2 c}{c+d}\right )}{b f (a+b) \sqrt {c+d \sec (e+f x)}}+\frac {2 d g \sqrt {g \sec (e+f x)} \sqrt {\frac {c \cos (e+f x)+d}{c+d}} \operatorname {EllipticPi}\left (2,\frac {1}{2} (e+f x),\frac {2 c}{c+d}\right )}{b f \sqrt {c+d \sec (e+f x)}}\)

input
Int[((g*Sec[e + f*x])^(3/2)*Sqrt[c + d*Sec[e + f*x]])/(a + b*Sec[e + f*x]) 
,x]
 
output
(2*d*g*Sqrt[(d + c*Cos[e + f*x])/(c + d)]*EllipticPi[2, (e + f*x)/2, (2*c) 
/(c + d)]*Sqrt[g*Sec[e + f*x]])/(b*f*Sqrt[c + d*Sec[e + f*x]]) + (2*(b*c - 
 a*d)*g*Sqrt[(d + c*Cos[e + f*x])/(c + d)]*EllipticPi[(2*a)/(a + b), (e + 
f*x)/2, (2*c)/(c + d)]*Sqrt[g*Sec[e + f*x]])/(b*(a + b)*f*Sqrt[c + d*Sec[e 
 + f*x]])
 

3.3.70.3.1 Defintions of rubi rules used

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3284
Int[1/(((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])*Sqrt[(c_.) + (d_.)*sin[(e_.) 
 + (f_.)*(x_)]]), x_Symbol] :> Simp[(2/(f*(a + b)*Sqrt[c + d]))*EllipticPi[ 
2*(b/(a + b)), (1/2)*(e - Pi/2 + f*x), 2*(d/(c + d))], x] /; FreeQ[{a, b, c 
, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 
0] && GtQ[c + d, 0]
 

rule 3286
Int[1/(((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])*Sqrt[(c_.) + (d_.)*sin[(e_.) 
 + (f_.)*(x_)]]), x_Symbol] :> Simp[Sqrt[(c + d*Sin[e + f*x])/(c + d)]/Sqrt 
[c + d*Sin[e + f*x]]   Int[1/((a + b*Sin[e + f*x])*Sqrt[c/(c + d) + (d/(c + 
 d))*Sin[e + f*x]]), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a* 
d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] &&  !GtQ[c + d, 0]
 

rule 4346
Int[(csc[(e_.) + (f_.)*(x_)]*(d_.))^(3/2)/Sqrt[csc[(e_.) + (f_.)*(x_)]*(b_. 
) + (a_)], x_Symbol] :> Simp[d*Sqrt[d*Csc[e + f*x]]*(Sqrt[b + a*Sin[e + f*x 
]]/Sqrt[a + b*Csc[e + f*x]])   Int[1/(Sin[e + f*x]*Sqrt[b + a*Sin[e + f*x]] 
), x], x] /; FreeQ[{a, b, d, e, f}, x] && NeQ[a^2 - b^2, 0]
 

rule 4459
Int[((csc[(e_.) + (f_.)*(x_)]*(g_.))^(3/2)*Sqrt[csc[(e_.) + (f_.)*(x_)]*(b_ 
.) + (a_)])/(csc[(e_.) + (f_.)*(x_)]*(d_.) + (c_)), x_Symbol] :> Simp[b/d 
 Int[(g*Csc[e + f*x])^(3/2)/Sqrt[a + b*Csc[e + f*x]], x], x] - Simp[(b*c - 
a*d)/d   Int[(g*Csc[e + f*x])^(3/2)/(Sqrt[a + b*Csc[e + f*x]]*(c + d*Csc[e 
+ f*x])), x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] && NeQ[b*c - a*d, 0] && 
 NeQ[a^2 - b^2, 0]
 

rule 4463
Int[(csc[(e_.) + (f_.)*(x_)]*(g_.))^(3/2)/(Sqrt[csc[(e_.) + (f_.)*(x_)]*(b_ 
.) + (a_)]*(csc[(e_.) + (f_.)*(x_)]*(d_.) + (c_))), x_Symbol] :> Simp[g*Sqr 
t[g*Csc[e + f*x]]*(Sqrt[b + a*Sin[e + f*x]]/Sqrt[a + b*Csc[e + f*x]])   Int 
[1/(Sqrt[b + a*Sin[e + f*x]]*(d + c*Sin[e + f*x])), x], x] /; FreeQ[{a, b, 
c, d, e, f, g}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0]
 
3.3.70.4 Maple [C] (verified)

Result contains complex when optimal does not.

Time = 8.49 (sec) , antiderivative size = 445, normalized size of antiderivative = 2.62

method result size
default \(-\frac {2 i g \sqrt {g \sec \left (f x +e \right )}\, \cos \left (f x +e \right ) \sqrt {c +d \sec \left (f x +e \right )}\, \sqrt {\frac {d +c \cos \left (f x +e \right )}{\left (c +d \right ) \left (\cos \left (f x +e \right )+1\right )}}\, \left (\operatorname {EllipticF}\left (i \left (\cot \left (f x +e \right )-\csc \left (f x +e \right )\right ), \sqrt {-\frac {c -d}{c +d}}\right ) a b c -\operatorname {EllipticF}\left (i \left (\cot \left (f x +e \right )-\csc \left (f x +e \right )\right ), \sqrt {-\frac {c -d}{c +d}}\right ) a b d +\operatorname {EllipticF}\left (i \left (\cot \left (f x +e \right )-\csc \left (f x +e \right )\right ), \sqrt {-\frac {c -d}{c +d}}\right ) b^{2} c -\operatorname {EllipticF}\left (i \left (\cot \left (f x +e \right )-\csc \left (f x +e \right )\right ), \sqrt {-\frac {c -d}{c +d}}\right ) b^{2} d -2 \operatorname {EllipticPi}\left (i \left (\cot \left (f x +e \right )-\csc \left (f x +e \right )\right ), -1, i \sqrt {\frac {c -d}{c +d}}\right ) a^{2} d +2 \operatorname {EllipticPi}\left (i \left (\cot \left (f x +e \right )-\csc \left (f x +e \right )\right ), -1, i \sqrt {\frac {c -d}{c +d}}\right ) b^{2} d +2 \operatorname {EllipticPi}\left (i \left (\cot \left (f x +e \right )-\csc \left (f x +e \right )\right ), -\frac {a -b}{a +b}, i \sqrt {\frac {c -d}{c +d}}\right ) a^{2} d -2 \operatorname {EllipticPi}\left (i \left (\cot \left (f x +e \right )-\csc \left (f x +e \right )\right ), -\frac {a -b}{a +b}, i \sqrt {\frac {c -d}{c +d}}\right ) a b c \right )}{f b \left (a -b \right ) \left (a +b \right ) \left (d +c \cos \left (f x +e \right )\right ) \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}}\) \(445\)

input
int((g*sec(f*x+e))^(3/2)*(c+d*sec(f*x+e))^(1/2)/(a+b*sec(f*x+e)),x,method= 
_RETURNVERBOSE)
 
output
-2*I*g/f/b/(a-b)/(a+b)*(g*sec(f*x+e))^(1/2)*cos(f*x+e)*(c+d*sec(f*x+e))^(1 
/2)*(1/(c+d)*(d+c*cos(f*x+e))/(cos(f*x+e)+1))^(1/2)*(EllipticF(I*(cot(f*x+ 
e)-csc(f*x+e)),(-(c-d)/(c+d))^(1/2))*a*b*c-EllipticF(I*(cot(f*x+e)-csc(f*x 
+e)),(-(c-d)/(c+d))^(1/2))*a*b*d+EllipticF(I*(cot(f*x+e)-csc(f*x+e)),(-(c- 
d)/(c+d))^(1/2))*b^2*c-EllipticF(I*(cot(f*x+e)-csc(f*x+e)),(-(c-d)/(c+d))^ 
(1/2))*b^2*d-2*EllipticPi(I*(cot(f*x+e)-csc(f*x+e)),-1,I*((c-d)/(c+d))^(1/ 
2))*a^2*d+2*EllipticPi(I*(cot(f*x+e)-csc(f*x+e)),-1,I*((c-d)/(c+d))^(1/2)) 
*b^2*d+2*EllipticPi(I*(cot(f*x+e)-csc(f*x+e)),-(a-b)/(a+b),I*((c-d)/(c+d)) 
^(1/2))*a^2*d-2*EllipticPi(I*(cot(f*x+e)-csc(f*x+e)),-(a-b)/(a+b),I*((c-d) 
/(c+d))^(1/2))*a*b*c)/(d+c*cos(f*x+e))/(1/(cos(f*x+e)+1))^(1/2)
 
3.3.70.5 Fricas [F(-1)]

Timed out. \[ \int \frac {(g \sec (e+f x))^{3/2} \sqrt {c+d \sec (e+f x)}}{a+b \sec (e+f x)} \, dx=\text {Timed out} \]

input
integrate((g*sec(f*x+e))^(3/2)*(c+d*sec(f*x+e))^(1/2)/(a+b*sec(f*x+e)),x, 
algorithm="fricas")
 
output
Timed out
 
3.3.70.6 Sympy [F]

\[ \int \frac {(g \sec (e+f x))^{3/2} \sqrt {c+d \sec (e+f x)}}{a+b \sec (e+f x)} \, dx=\int \frac {\left (g \sec {\left (e + f x \right )}\right )^{\frac {3}{2}} \sqrt {c + d \sec {\left (e + f x \right )}}}{a + b \sec {\left (e + f x \right )}}\, dx \]

input
integrate((g*sec(f*x+e))**(3/2)*(c+d*sec(f*x+e))**(1/2)/(a+b*sec(f*x+e)),x 
)
 
output
Integral((g*sec(e + f*x))**(3/2)*sqrt(c + d*sec(e + f*x))/(a + b*sec(e + f 
*x)), x)
 
3.3.70.7 Maxima [F]

\[ \int \frac {(g \sec (e+f x))^{3/2} \sqrt {c+d \sec (e+f x)}}{a+b \sec (e+f x)} \, dx=\int { \frac {\sqrt {d \sec \left (f x + e\right ) + c} \left (g \sec \left (f x + e\right )\right )^{\frac {3}{2}}}{b \sec \left (f x + e\right ) + a} \,d x } \]

input
integrate((g*sec(f*x+e))^(3/2)*(c+d*sec(f*x+e))^(1/2)/(a+b*sec(f*x+e)),x, 
algorithm="maxima")
 
output
integrate(sqrt(d*sec(f*x + e) + c)*(g*sec(f*x + e))^(3/2)/(b*sec(f*x + e) 
+ a), x)
 
3.3.70.8 Giac [F]

\[ \int \frac {(g \sec (e+f x))^{3/2} \sqrt {c+d \sec (e+f x)}}{a+b \sec (e+f x)} \, dx=\int { \frac {\sqrt {d \sec \left (f x + e\right ) + c} \left (g \sec \left (f x + e\right )\right )^{\frac {3}{2}}}{b \sec \left (f x + e\right ) + a} \,d x } \]

input
integrate((g*sec(f*x+e))^(3/2)*(c+d*sec(f*x+e))^(1/2)/(a+b*sec(f*x+e)),x, 
algorithm="giac")
 
output
integrate(sqrt(d*sec(f*x + e) + c)*(g*sec(f*x + e))^(3/2)/(b*sec(f*x + e) 
+ a), x)
 
3.3.70.9 Mupad [F(-1)]

Timed out. \[ \int \frac {(g \sec (e+f x))^{3/2} \sqrt {c+d \sec (e+f x)}}{a+b \sec (e+f x)} \, dx=\int \frac {\sqrt {c+\frac {d}{\cos \left (e+f\,x\right )}}\,{\left (\frac {g}{\cos \left (e+f\,x\right )}\right )}^{3/2}}{a+\frac {b}{\cos \left (e+f\,x\right )}} \,d x \]

input
int(((c + d/cos(e + f*x))^(1/2)*(g/cos(e + f*x))^(3/2))/(a + b/cos(e + f*x 
)),x)
 
output
int(((c + d/cos(e + f*x))^(1/2)*(g/cos(e + f*x))^(3/2))/(a + b/cos(e + f*x 
)), x)